# What are The Magnitude and Direction of The Net Force on The Circuit?

The right edge of the circuit in the Figure extends into a 50mT uniform magnetic field. **What are The Magnitude and Direction of The Net Force on The Circuit?**

A) There is zero force exerted on the loop.

B) 25mN to the left.

C) 25mN to the right.

D) 75mN to the right.

E) 75mN to the left.

**Answer: C) 25mN to the right**

### Explanation:

Here we get from
this circuit,

The magnitude of the
Magnetic Field, B= 50mT =50×10^{-3}T

Length, L= 10cm= 0.1m

Potential Difference, V= 15v

We can find the Current by using Ohm’s law,

The angle between the Current element and Magnetic Field, ɵ= 90𑄨

Magnetic Force acting on that segment, F= ILBsinɵ

= 5.0A×0.1m×50×10^{-3}T×sin90𑄨

=25×10^{-3}N

= 25mN

Using Fleming Left Hand Rule,

**The Direction of this force is towards the Right.**

## Related FAQs

**What is The Net Force of a Circuit?**

The net force of a circuit is the force that is exerted on the circuit by the electric and magnetic fields. This force is responsible for the movement of the charges in the circuit.

### How do you calculate the net force of a circuit in a magnetic field?

The net force of a circuit in a magnetic field can be calculated by using the following equation:

F= ILBsinɵ

Where:

F is the net force (in Newtons)

B is the magnetic field strength (in Teslas)

I is the current flowing through the circuit (in Amperes)

L is the length of the circuit (in meters)

This equation can be used to calculate the force exerted by a magnetic field on a current-carrying conductor. The force is perpendicular to both the magnetic field and the current and is given by the product of these two quantities.